If it's not what You are looking for type in the equation solver your own equation and let us solve it.
n^2-3n-208=0
a = 1; b = -3; c = -208;
Δ = b2-4ac
Δ = -32-4·1·(-208)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-29}{2*1}=\frac{-26}{2} =-13 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+29}{2*1}=\frac{32}{2} =16 $
| x3.21=9.63 | | 58=2(x+5)+2(3x) | | 3x-4x=5-9 | | 5x-3=11-3x | | -8n+6=-6n-10 | | 5x—4(2x+11)=13 | | x-7.55=14.95 | | -14=2(x-1) | | -21-(-44)=x/10 | | 9h^2-3h=0 | | 9x-5/2=7/3 | | 3=h/3.3 | | 9+a/6=1 | | 34-18=2(x-2) | | 12y+20=80 | | 5/2x+6=7/4x−8 | | 4(x-5)=48•12 | | 6y^2-6y=0 | | 52x+6=74x−8 | | 4(x-5)=48x12 | | 43+4y-16=16y-13-4y | | 29=w/4-14 | | 2-2m=5-5m | | 27-7(x-4)+4(2x-3=0 | | 2(4x-3)=10+× | | 1.6+4b=8 | | x/5-28=8 | | 8n-5=3n+25 | | 7(x+4)+3x=98 | | 1x+20=-8 | | -p-1=p-214 | | 24x=6(3x+5) |